Botryobasidium zhejiangensis Xin Li, A. H. Zhu, Yuan Yuan & Y. D. Wu, 2025

Li, Xin, Zhang, Xin, Sun, Yi-Fei, Li, Zhen-Hao, Zhu, An-Hong & Wu, Ying-Da, 2025, Morphological and molecular identification for two new wood-inhabiting species of Botryobasidium (Basidiomycota) from China, MycoKeys 116, pp. 73-89 : 73-89

publication ID

https://doi.org/10.3897/mycokeys.116.143594

DOI

https://doi.org/10.5281/zenodo.15183725

persistent identifier

https://treatment.plazi.org/id/4E2381D1-C2F4-5548-92C2-66F974BB6181

treatment provided by

MycoKeys by Pensoft

scientific name

Botryobasidium zhejiangensis Xin Li, A. H. Zhu, Yuan Yuan & Y. D. Wu
status

sp. nov.

Botryobasidium zhejiangensis Xin Li, A. H. Zhu, Yuan Yuan & Y. D. Wu sp. nov.

Figs 4 View Figure 4 , 5 View Figure 5

Holotype.

China • Zhejiang Province, Jinhua, Wuyi County, Guodong Village , on rotten wood of Pinus massoniana , 18 June 2023, Dai 25056 ( BJFC 042609 About BJFC ).

Etymology.

Zhejiangensis refers to the type location, Zhejiang Province, East China.

Description.

Basidiomata: Annual, resupinate, adnate, pellicular, difficult to separate from substrate, up to 11 cm long, 7 cm wide, 1 mm thick, without odor and taste when fresh; hymenophore white to cream, smooth, uncracked, cream to slightly buff when dry; sterile margin indistinct, thinning out, concolorous with hymenophore.

Hyphal system: Monomitic, generative hyphae with clamp connections, CB +, IKI –; tissues unchanged in KOH. Subhymenial hyphae hyaline, thin-walled, smooth, frequently branched at right angles, loosely interwoven, 4–6 µm in diam.; subicular hyphae hyaline, slightly thick-walled, smooth, frequently branched, 6–8 µm in diam.

Hymenium: Basidia slightly barrel-shaped, hyaline, thin-walled, with six sterigmata and a basal clamp connection, 15–19 × 5–6 μm; basidioles in shape similar to basidia, but smaller.

Spores: Basidiospores more or less navicular, hyaline, thin-walled, smooth, CB +, IKI –, (7.8 –) 7.9–9.2 (– 9.5) × (2.5 –) 2.6–3.4 (– 3.5) μm, L = 8.47 μm, W = 3.05 μm, Q = 2.78 (n = 60 / 2).